%I #5 Mar 31 2012 12:36:19
%S 0,2,4,6,12,0,12,36,40,12,20,76,166,144,0,30,143,483,922,550,40,42,
%T 233,1126,3481,5136,1896,0,56,366,2276,9904,25306,28656,7584,140,72,
%U 536,4150,23400,88509,191456,162028,27328,0,90,760,6946,48491,249119,834717
%N T(n,k)=Number of arrangements of n+1 nonzero numbers x(i) in -k..k with the sum of div(x(i),x(i+1)), where div(a,b)=a/b produces the integer quotient implying a nonnegative remainder, equal to zero
%C Table starts
%C ...0......2........6........12.........20..........30...........42...........56
%C ...4.....12.......36........76........143.........233..........366..........536
%C ...0.....40......166.......483.......1126........2276.........4150.........6946
%C ..12....144......922......3481.......9904.......23400........48491........92478
%C ...0....550.....5136.....25306......88509......249119.......599181......1291797
%C ..40...1896....28656....191456.....834717.....2783714......7737762.....18951546
%C ...0...7584...162028...1436962....7843113....31391655....101530262....282859251
%C .140..27328...910716..10802667...73725405...353856100...1333341624...4232955454
%C ...0.105348..5162308..81709584..697624797..4017545773..17643516841..63898862902
%C .504.398760.29554964.622881909.6644826507.45918810745.235162515839.972408511316
%H R. H. Hardin, <a href="/A190071/b190071.txt">Table of n, a(n) for n = 1..793</a>
%e Some solutions for n=6 k=4
%e .-3...-4....2....1....3...-3...-4....1....2...-1...-3....2...-1....1....2...-2
%e .-1...-4...-4...-3...-2...-2...-2...-2...-3...-1...-1...-1...-2...-2...-3...-4
%e ..3....2....1....2....4....1....4...-2...-2...-3....1....3...-3....3...-2...-2
%e .-1....2....1....4....2...-2...-3....2....4....1....2....3...-2....1...-3....1
%e .-1....4...-2....3...-1....3....3...-4...-1....2....3...-4....2...-2....2....3
%e ..4....3...-1....4...-3....2....3...-4...-4....2...-4...-4...-1....3....4....2
%e ..3...-2...-1....3...-3...-3....4....4...-3....4....3...-4....1...-3...-3...-1
%Y Column 1 is A028329(n/2) for even n
%Y Row 1 is A002378(n-1)
%K nonn,tabl
%O 1,2
%A _R. H. Hardin_ May 04 2011
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