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A189321
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Number of nondecreasing arrangements of n+2 numbers in 0..4 with the last equal to 4 and each after the second equal to the sum of one or two of the preceding four.
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1
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7, 12, 20, 32, 49, 70, 94, 120, 148, 178, 210, 244, 280, 318, 358, 400, 444, 490, 538, 588, 640, 694, 750, 808, 868, 930, 994, 1060, 1128, 1198, 1270, 1344, 1420, 1498, 1578, 1660, 1744, 1830, 1918, 2008, 2100, 2194, 2290, 2388, 2488, 2590, 2694, 2800, 2908
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OFFSET
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1,1
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COMMENTS
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LINKS
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FORMULA
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Empirical: a(n) = n^2 + 11*n - 32 for n>5.
Empirical g.f.: x*(7 - 9*x + 5*x^2 + x^3 + x^4 - x^5 - x^6 - x^7) / (1 - x)^3. - Colin Barker, May 02 2018
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EXAMPLE
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Some solutions for n=3:
..1....1....3....0....1....2....1....1....1....4....1....0....1....1....2....1
..3....2....4....4....3....2....3....1....2....4....2....2....2....1....2....4
..4....2....4....4....3....4....3....2....3....4....3....2....2....2....2....4
..4....2....4....4....4....4....3....2....3....4....4....2....3....3....2....4
..4....4....4....4....4....4....4....4....4....4....4....4....4....4....4....4
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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