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Positions of 0 in A188398; complement of A188265.
3

%I #8 Apr 12 2018 02:45:48

%S 2,3,6,9,10,13,16,17,19,20,23,26,27,30,33,34,36,37,40,43,44,47,50,51,

%T 54,57,58,60,61,64,67,68,71,74,75,77,78,81,84,85,88,91,92,95,98,99,

%U 101,102,105,108,109,112,115,116,118,119,122,125,126,129,132,133,135,136,139,142,143,146,149,150,153,156,157,159,160

%N Positions of 0 in A188398; complement of A188265.

%C See A187950, A188398.

%H G. C. Greubel, <a href="/A188399/b188399.txt">Table of n, a(n) for n = 1..10000</a>

%t r=2^(-1/2); k=5;

%t t=Table[Floor[n*r+k*r]-Floor[n*r]-Floor[k*r], {n,1,220}] (* A188398 *)

%t Flatten[Position[t,0] ] (* A188399 *)

%t Flatten[Position[t,1] ] (* A188265 *)

%Y Cf. A187950, A188398, A188265.

%K nonn

%O 1,1

%A _Clark Kimberling_, Mar 30 2011