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[nr]-[kr]-[nr-kr], where r=sqrt(3), k=5, [ ]=floor.
3

%I #4 Mar 30 2012 18:57:22

%S 0,1,1,0,0,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,1,0,1,1,0,0,1,1,0,

%T 1,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,1,0,

%U 1,1,0,0,1,1,0,1,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,0,0,1,1,0,1,1,1,0,1,1,1

%N [nr]-[kr]-[nr-kr], where r=sqrt(3), k=5, [ ]=floor.

%C See A188014.

%F a(n)=[nr]-[5r]-[nr-5r], where r=sqrt(3).

%t r=3^(1/2)); k=5;

%t t=Table[Floor[n*r]-Floor[(n-k)*r]-Floor[k*r],{n,1,220}] (*A188076*)

%t Flatten[Position[t,0]] (*A188077*)

%t Flatten[Position[t,1]] (*A188078*)

%Y Cf. A188014, A188077, A188078.

%K nonn

%O 1

%A _Clark Kimberling_, Mar 20 2011