OFFSET
1,1
COMMENTS
The first 10000 terms are all divisible by 210.
LINKS
Donovan Johnson, Table of n, a(n) for n = 1..10000
EXAMPLE
Summands are odd abundant numbers.
a(1) = 1890 = 945 + 945.
a(2) = 3150 = 945 + 2205 = 1575 + 1575.
a(3) = 4410 = 945 + 3465 = 1575 + 2835 = 2205 + 2205.
a(4) = 5670 = 945 + 4725 = 1575 + 4095 = 2205 + 3465 = 2835 + 2835.
PROG
(PARI) /* finds first 1000 terms */ mx=4616430; ct=vector(mx); k=9384; v=vector(k); n=vector(1000); c=0; forstep(i=945, mx-1, 2, if(sigma(i)-2*i>0, c++; v[c]=i)); for(i=1, k, for(j=i, k, s=v[i]+v[j]; if(s<=mx, ct[s]++, next(2)))); forstep(i=1890, mx, 2, if(ct[i]>0 && ct[i]<=1000 && n[ct[i]]==0, n[ct[i]]=i)); for(i=1, 1000, write("b187743.txt", i " " n[i]))
CROSSREFS
KEYWORD
nonn
AUTHOR
Donovan Johnson, Jan 03 2013
STATUS
approved