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%I #5 Dec 04 2016 19:46:24
%S 1,3,4,5,7,8,10,12,13,15,16,18,19,20,22,23,25,27,28,29,31,32,34,35,37,
%T 39,40,42,43,44,46,48,49,51,52,53,55,56,58,60,61,63,64,66,67,68,70,72,
%U 73,75,76,77,79,80,82,83,85,87,88,90,91,92,94,95,97,99,100,101,103,104,106,108,109,111,112,114,115,116,118,119,121,123,124,125,127,128,130,131,133,135,136,138,139
%N Rank transform of the sequence round(3n/4); complement of A187690.
%C See A187224.
%t seqA = Table[Round[3n/4], {n, 1, 220}]
%t seqB = Table[n, {n, 1, 220}];(*A000027*)
%t jointRank[{seqA_,
%t seqB_}] := {Flatten@Position[#1, {_, 1}],
%t Flatten@Position[#1, {_, 2}]} &[
%t Sort@Flatten[{{#1, 1} & /@ seqA, {#1, 2} & /@ seqB}, 1]];
%t limseqU =
%t FixedPoint[jointRank[{seqA, #1[[1]]}] &,
%t jointRank[{seqA, seqB}]][[1]] (*A187689*)
%t Complement[Range[Length[seqA]], limseqU] (*A187690*)
%t (*by _Peter J. C. Moses_, Mar 12 2011*)
%Y Cf. A187224, A187690.
%K nonn
%O 1,2
%A _Clark Kimberling_, Mar 12 2011