%I #5 Mar 30 2012 17:26:37
%S 2,2,3,2,2,3,2,5,2,2,3,2,5,2,3,7,2,2,3,2,2,3,5,2,2,7,2,3,5,2,2,11,3,7,
%T 2,2,3,2,11,2,5,2,3,13,2,5,7,2,3,2,2,3,7,2,2,11,3,2,5,13,2,2,3,11,5,2,
%U 17,7,2,13,3,2,2,3,2,17,2,5,2,3,19,11,2,2,5,3,13,2,2,7,3,2,2
%N a(n) = the least proper divisor of A187104(n) (Numbers with property that the largest proper divisor is a cube).
%C All terms in A187104 are of the form p*m^3 where p is prime and the least proper divisor of m is not less than p. The sequence gives values of p while values of m are in A187112.
%Y a(n)=A187104(n)/(A187112(n))^3.
%K nonn
%O 1,1
%A _Zak Seidov_, Mar 05 2011
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