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%I #17 Apr 29 2016 05:14:06
%S 1,6,41,298,2720,24688,232970,2255588,22228377,220476980,2197066826
%N Total number of n-digit numbers requiring 4 positive biquadrates in their representation as sum of biquadrates.
%C A102831(n) + A186650(n) + A186652(n) + a(n) + A186656(n) + A186658(n) + A186660(n) + A186662(n) + A186664(n) + A186666(n) + A186668(n) + A186670(n) + A186672(n) + A186674(n) + A186676(n) + A186678(n) + A186681(n) + A186683(n) + A186685(n) = A052268(n), for n>1.
%H Eric Weisstein's World of Mathematics, <a href="http://mathworld.wolfram.com/WaringsProblem.html">Waring's Problem.</a>
%F a(n) = A186653(n) - A186653(n-1).
%Y Cf. A003338, A186653.
%K nonn,base,more
%O 1,2
%A _Martin Renner_, Feb 25 2011
%E a(5)-a(11) from _Giovanni Resta_, Apr 26 2016
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