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A186287 a(n) is the denominator of the rational number whose "factorization" into terms of A186285 has the balanced ternary representation corresponding to n. 5
1, 1, 2, 1, 1, 6, 3, 3, 2, 1, 1, 2, 1, 1, 30, 15, 15, 10, 5, 5, 10, 5, 5, 6, 3, 3, 2, 1, 1, 2, 1, 1, 6, 3, 3, 2, 1, 1, 2, 1, 1, 105, 105, 105, 35, 35, 35, 35, 35, 35, 21, 21, 21, 7, 7, 7, 7, 7, 7, 21, 21, 21, 7, 7, 7, 7, 7, 7, 15, 15, 15, 5, 5, 5, 5, 5, 5, 3, 3, 3, 1, 1, 1, 1, 1, 1, 3, 3, 3 (list; graph; refs; listen; history; text; internal format)
OFFSET
0,3
COMMENTS
Denominators from the ordering of positive rational numbers by increasing balanced ternary representation of the "factorization" of positive rational numbers into terms of A186285 (prime powers with a power of three as exponent).
LINKS
FORMULA
The balanced ternary representation of n
n = Sum(i=0..1+floor(log_3(2|n|)) n_i * 3^i, n_i in {-1,0,1},
is taken as the representation of the "factorization" of the positive rational number c(n)/d(n) into terms from A186285
c(n)/d(n) = Prod(i=0..1+floor(log_3(2|n|)) (A186285(i+1))^(n_i), where A186285(i+1) is the (i+1)th prime power with exponent being a power of 3. Then a(n) is the denominator, i.e., d(n).
EXAMPLE
The balanced ternary digits {-1,0,+1} are represented here as {2,0,1}.
n BalTern A186286/A186287 (in reduced form)
0 0 Empty product = 1 = 1/1, a(n) = 1
1 1 2 = 2/1, a(n) = 1
2 12 3*(1/2) = 3/2, a(n) = 2
3 10 3 = 3/1, a(n) = 1
4 11 3*2 = 6 = 6/1, a(n) = 1
5 122 5*(1/3)*(1/2) = 5/6, a(n) = 6
6 120 5*(1/3) = 5/3, a(n) = 3
7 121 5*(1/3)*2 = 10/3, a(n) = 3
... ...
41 12222 8*(1/7)*(1/5)*(1/3)*(1/2) = 8/210 = 4/105, a(n) = 105
CROSSREFS
Sequence in context: A172400 A226691 A158389 * A318393 A340128 A139622
KEYWORD
nonn,frac
AUTHOR
Daniel Forgues, Feb 17 2011
STATUS
approved

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Last modified April 19 05:19 EDT 2024. Contains 371782 sequences. (Running on oeis4.)