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A186261
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a(n) = 9*b_9(n) + 8, where b_9 lists the indices of zeros of the sequence A261309: u(n) = abs(u(n-1) - gcd(u(n-1), 9n-1)), u(1) = 1.
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2
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26, 269, 2699, 26423, 259829, 2595473, 25954289, 259491059, 2594910599, 25949104721, 259491047219, 2594905133453, 25949039883929, 259490398799609, 2594903521711517, 25949035214699921, 259490352146949701, 2594903520789157301, 25949035207891572929, 259490352078915446897
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OFFSET
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1,1
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COMMENTS
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For any fixed integer m>=1 define u(1)=1 and u(n)=abs(u(n-1)-gcd(u(n-1),m*n-1)). Then (b_m(k))_{k>=1} is the sequence of integers such that u(b_m(k))=0 and we conjecture that for k large enough m*b_m(k)+m-1 is a prime number. Here for m=9 it appears a(n) is prime for n>=2.
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LINKS
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FORMULA
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We conjecture that a(n) is asymptotic to c*10^n with c>0.
See the wiki link for a sketch of a proof of this conjecture. We find c=2.59490352... - M. F. Hasler, Aug 22 2015
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PROG
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(PARI) a=1; m=9; for(n=2, 1e8, a=abs(a-gcd(a, m*n-1)); if(a==0, print1(m*n+m-1, ", ")))
(PARI) m=9; a=0; k=2; for(n=1, 20, while(1<#(f=factor(N=m*(k+a)+m-1)[, 1]) && a, k+=1+D=vecmin(apply(p->a%p, f)); a-=D+gcd(a-D, N)); k+=a+1; print1(a=N, ", ")) \\ M. F. Hasler, Aug 22 2015
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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