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A186251
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2n-th derivative of sec(x)^cosh(x) at x=0.
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1
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1, 1, 11, 196, 6621, 331816, 23484911, 2215289896, 268265691081, 40520069205136, 7462406090362331, 1645244324233761736, 427705624174427756061, 129446242864616486729896, 45117167155416556090204871, 17939982317115194446562110816, 8071743191485825080634857996561
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OFFSET
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0,3
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COMMENTS
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sec(x) = 1/cos(x).
The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
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LINKS
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FORMULA
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a(n) = (2n)! * [x^(2n)] sec(x)^cosh(x).
a(n) ~ 2^(4*n+2*cosh(Pi/2)+1) * n^(2*n+cosh(Pi/2)-1/2) / (GAMMA(cosh(Pi/2)) * exp(2*n) * Pi^(2*n+cosh(Pi/2)-1/2)). - Vaclav Kotesovec, Aug 22 2014
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MAPLE
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b:= n-> n! *coeff(series(sec(x)^cosh(x), x, n+1), x, n):
a:= n-> b(2*n):
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MATHEMATICA
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f[x_] := Sec[x]^Cosh[x]; Table[Derivative[2*n] [f][0], {n, 0, 17}]
nmax=40; Table[(CoefficientList[Series[Sec[x]^Cosh[x], {x, 0, nmax}], x] *Range[0, nmax]!)[[n]], {n, 1, nmax, 2}] (* Vaclav Kotesovec, Aug 22 2014 *)
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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