login
A186249
2n-th derivative of sec(x)^sec(x) at x=0.
1
1, 1, 11, 256, 10541, 672136, 61001951, 7445096296, 1172998147241, 231333927486736, 55747918840676411, 16100914826854576456, 5485174647349481371661, 2175023364205612725532456, 992565740287786208277022391, 516241740263310751317668520736
OFFSET
0,3
COMMENTS
sec(x) = 1/cos(x).
The sequence gives only 2n-th derivatives because (2n+1)-th derivatives are 0.
MATHEMATICA
f[x_] := Sec[x]^Sec[x]; Table[Derivative[2*n] [f][0], {n, 0, 18}]
CROSSREFS
Cf. A186250.
Sequence in context: A128405 A377426 A052782 * A186250 A324327 A142208
KEYWORD
nonn
AUTHOR
Michel Lagneau, Aug 18 2012
STATUS
approved