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A186080
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Fourth powers that are palindromic in base 10.
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1
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0, 1, 14641, 104060401, 1004006004001, 10004000600040001, 100004000060000400001, 1000004000006000004000001, 10000004000000600000040000001, 100000004000000060000000400000001
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OFFSET
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1,3
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COMMENTS
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See A056810 (the main entry for this problem) for further information, including the search limit. - N. J. A. Sloane, Mar 07 2011.
Conjecture: If k^4 is a palindrome > 0, then k begins and ends with digit 1, all other digits of k being 0.
The number of zeros in 1x1, where the x are zeros, is the same as (the number of zeros)/4 in (1x1)^4 = 1x4x6x4x1.
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LINKS
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Table of n, a(n) for n=1..10.
P. De Geest, Palindromic cubes (Simmons test is mentioned here)
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FORMULA
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a(n) = A056810(n)^4
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MATHEMATICA
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Do[If[Module[{idn = IntegerDigits[n^4, 10]}, idn == Reverse[idn]], Print[n^4]], {n, 100000001}]
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PROG
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(MAGMA) [ p: n in [0..10000000] | s eq Reverse(s) where s is Intseq(p) where p is n^4 ];
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CROSSREFS
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Cf. A002113, A168576, A056810, A002778, A002779.
Sequence in context: A017284 A017392 A017656 * A013861 A015312 A219068
Adjacent sequences: A186077 A186078 A186079 * A186081 A186082 A186083
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KEYWORD
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nonn,base
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AUTHOR
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Matevz Markovic, Feb 11 2011
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STATUS
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approved
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