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Number of arrangements of n+3 numbers in 0..5 with each number being the sum mod 6 of three others
1

%I #5 Mar 31 2012 12:35:55

%S 8,982,20152,201154,1466628,9469778,58702904,357576342,2161032260,

%T 13012476622,78214995120,469720252818,2819655668996,16922097475386,

%U 101545629217608,609314732885086,3656017115990916,21936507241621846

%N Number of arrangements of n+3 numbers in 0..5 with each number being the sum mod 6 of three others

%C Column 5 of A183892

%H R. H. Hardin, <a href="/A183888/b183888.txt">Table of n, a(n) for n = 1..58</a>

%e Some solutions for n=2

%e ..4....1....4....4....0....1....0....2....4....3....4....2....3....1....1....0

%e ..1....0....3....1....5....2....1....0....3....4....5....3....5....4....1....3

%e ..2....3....5....4....4....3....2....3....0....5....2....5....1....0....3....0

%e ..0....2....1....5....1....0....3....1....5....1....3....1....3....1....1....3

%e ..3....4....0....3....3....4....5....5....1....4....0....0....1....2....3....0

%K nonn

%O 1,1

%A _R. H. Hardin_ Jan 07 2011