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A183821 1/256 the number of (n+1) X 3 0..3 arrays with no 2 X 2 subblock being a reflection across the shared element pair of any horizontal or vertical neighbor. 1

%I #16 Aug 12 2018 02:43:48

%S 15,813,43947,2377341,128578815,6954559893,376152548283,

%T 20345104031589,1100412240703119,59518368554767389,

%U 3219189893127084843,174117402720326269485,9417546276713264441151,509369980225226329837125

%N 1/256 the number of (n+1) X 3 0..3 arrays with no 2 X 2 subblock being a reflection across the shared element pair of any horizontal or vertical neighbor.

%C Column 2 of A183827.

%H R. H. Hardin, <a href="/A183821/b183821.txt">Table of n, a(n) for n = 1..147</a>

%H Robert Israel, <a href="/A183821/a183821.pdf">Maple-assisted proof of formula</a>

%F Empirical: a(n) = 43*a(n-1) + 645*a(n-2) - 2451*a(n-3).

%F Empirical g.f.: 3*x*(5 + 56*x - 229*x^2) / (1 - 43*x - 645*x^2 + 2451*x^3). - _Colin Barker_, Apr 05 2018

%F Empirical formulas verified (see link). - _Robert Israel_, Aug 10 2018

%e Some solutions with upper left block zero for 5 X 3:

%e 0 0 2 0 0 0 0 0 3 0 0 3 0 0 0 0 0 2 0 0 0

%e 0 0 0 0 0 1 0 0 3 0 0 2 0 0 1 0 0 1 0 0 2

%e 2 0 0 2 0 1 3 0 2 1 0 2 1 0 3 1 0 0 3 0 1

%e 2 2 1 3 2 3 1 3 1 1 3 1 0 3 3 2 1 2 0 3 3

%e 3 2 3 0 0 3 0 0 3 2 0 3 3 2 2 0 0 3 2 2 0

%p Configs:= remove(t -> [t[1],t[4]]=[t[3],t[6]], [seq(convert(4^6+i,base,4)[1..6],i=0..4^6-1)]): nConfigs:= nops(Configs):

%p Compatible:= proc(i,j) local k;

%p if Configs[i][4..6] <> Configs[j][1..3] or Configs[i][1..2] =Configs[j][4..5] or Configs[i][2..3] = Configs[j][5..6] then 0 else 1 fi;

%p end proc:

%p T:= Matrix(nConfigs,nConfigs,Compatible):

%p u:= Vector(nConfigs,1):

%p Tu[0]:= u:

%p for n from 1 to 30 do Tu[n]:= T . Tu[n-1] od:

%p seq(u^%T . Tu[n]/256, n=0..30); # _Robert Israel_, Aug 10 2018

%Y Cf. A183827.

%K nonn

%O 1,1

%A _R. H. Hardin_, Jan 07 2011

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Last modified April 25 10:39 EDT 2024. Contains 371967 sequences. (Running on oeis4.)