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A183163
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Least integer k such that floor(k*log(n+1))>k*log(n).
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5
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2, 1, 3, 2, 3, 5, 1, 6, 4, 3, 5, 2, 5, 3, 4, 5, 6, 10, 18, 1, 11, 8, 6, 5, 4, 7, 10, 3, 5, 7, 9, 15, 2, 11, 7, 5, 8, 14, 3, 10, 7, 4, 9, 5, 11, 6, 7, 8, 10, 12, 15, 21, 34, 1, 40, 24, 17, 13, 11, 10, 8, 7, 13, 6, 11, 5, 14, 9, 17, 4, 11, 7, 10, 13, 22, 3, 17
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OFFSET
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1,1
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COMMENTS
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Equivalently, a(n) is the least integer k for which there is an integer J such that n^k < e^J < (n+1)^k; or, equivalently, such that there is a rational number H with denominator k for which log(n) < H < log(n+1).
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LINKS
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MATHEMATICA
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Table[k=1; While[Floor[k*Log[n+1]] <= k*Log[n], k++]; k, {n, 100}]
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PROG
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(Sage) A183163 = lambda n: next(k for k in IntegerRange(1, infinity) if floor(k*log(n+1)) > k*log(n)) # D. S. McNeil, Dec 28 2010
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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