OFFSET
1,7
COMMENTS
A083051(n) = 2*n+1 + floor(n*sqrt(2)) is the location of the least k for which a(k)=n.
LINKS
G. C. Greubel, Table of n, a(n) for n = 1..10000
FORMULA
a(n) = floor(n/(2+sqrt(2))).
MATHEMATICA
With[{c=2+Sqrt[2]}, Table[Floor[n/c], {n, 80}]] (* Harvey P. Dale, Jun 21 2017 *)
PROG
(PARI) for(n=1, 100, print1(floor(n/(2+sqrt(2))), ", ")) \\ G. C. Greubel Apr 10 2018
(Magma) [Floor(n/(2+Sqrt(2))): n in [1..100]]; // G. C. Greubel, Apr 10 2018
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Dec 26 2010
STATUS
approved