OFFSET
1,1
COMMENTS
Let u=2^(1/3). Jointly rank {j*u} and {k/u} as in the first comment at A182760; a(n) is the position of n*u.
LINKS
Paolo Xausa, Table of n, a(n) for n = 1..10000
Eric Weisstein's World of Mathematics, Beatty Sequence.
FORMULA
a(n) = floor(n*(1+2^(2/3))).
MATHEMATICA
Floor[Range[100]*(1 + 2^(2/3))] (* Paolo Xausa, Jul 09 2024 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Clark Kimberling, Nov 30 2010
STATUS
approved