%I #2 Mar 30 2012 18:57:11
%S 3,4,6,8,11,12,16,19,20,21,24,25,27,29,32,33,37,38,40,41,42,45,46,50,
%T 53,54,55,58,59,61,63,66,67,71,72,74,75,76,79,80,82,84,87,88,92,93,95,
%U 97,100,101,105,108,109,110,113,114,116,118,121,122,126,127,129,130,131
%N Solutions of A181712(n)=1.
%e A181712 begins with 0,0,1,1,0,1,0,1,0,0,1,1,0,0,0,1,0,0,1,1,1,0,0,
%e so that A181714 begins with 3,4,6,8,11,12,16,19,20,21.
%Y Cf. A181712, A181713.
%K nonn
%O 1,1
%A _Clark Kimberling_, Nov 07 2010
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