login
This site is supported by donations to The OEIS Foundation.

 

Logo


Hints
(Greetings from The On-Line Encyclopedia of Integer Sequences!)
A181711 Numbers of the form m*(2^k-1), where m = 2^(k-1)*(2^k-1) is a perfect number (A000396). 0
18, 196, 15376, 1032256, 274810802176, 1125882727038976, 72057319160283136, 4951760152529835082242850816, 6129982163463555428116476125461573244012649752219877376 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

The associated exponents k are in A000043: 2, 3, 5, 7, 13, 17, 19 ,31, 61, ...

One can prove that, if m = 2^(k-1)*(2^k-1) is a perfect number, then m*2^k and m*(2^k-1) are both in A181595. Thus every even term in A000396 is a difference of two terms in A181595.

LINKS

Table of n, a(n) for n=1..9.

FORMULA

If odd perfect numbers do not exist, then a(n) = A181710(n) - A000396(n).

a(n) = A019279(n)*(A000668(n))^2 if there are no odd superperfect numbers. - César Aguilera, Jun 13 2017

EXAMPLE

With k=3, m = 2^(k-1)*(2^k - 1) = 2^2*(8 - 1) = 28 is a perfect number (A000396), so m*(2^k - 1) = 28*7 = 196 is in the sequence. - Michael B. Porter, Jul 19 2016

CROSSREFS

Cf. A000043, A000396, A181595, A181596, A181701, A181710.

Sequence in context: A125406 A318161 A182311 * A042940 A264356 A034727

Adjacent sequences:  A181708 A181709 A181710 * A181712 A181713 A181714

KEYWORD

nonn

AUTHOR

Vladimir Shevelev, Nov 07 2010

EXTENSIONS

Definition condensed by R. J. Mathar, Dec 05 2010

STATUS

approved

Lookup | Welcome | Wiki | Register | Music | Plot 2 | Demos | Index | Browse | More | WebCam
Contribute new seq. or comment | Format | Style Sheet | Transforms | Superseeker | Recent
The OEIS Community | Maintained by The OEIS Foundation Inc.

License Agreements, Terms of Use, Privacy Policy. .

Last modified March 19 15:02 EDT 2019. Contains 321330 sequences. (Running on oeis4.)