|
|
A181585
|
|
"Early bird" squares: write the square numbers in a string 149162536496481100... . Sequence gives numbers k such that k^2 occurs in the string ahead of its natural place.
|
|
1
|
|
|
7, 8, 21, 25, 46, 97, 129, 161, 196, 221, 245, 258, 277, 296, 350, 436, 460, 592, 661, 694, 789, 804, 875, 877, 1250, 2025, 2221, 3500, 3959, 4020, 5461, 5920, 7925, 9607, 12500, 14772, 19821, 20010, 21825, 22011, 22221, 24012, 25225, 25375, 25388, 26013, 28014
(list;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
1,1
|
|
COMMENTS
|
Corresponding positions of the k^2's in a string 149162536496481100... are 2, 9, 23, 5, 112, 209, 395, 336, 496, 465, 656, 935, 65, 486, 603, 75, 112, 1115, 2317, 3163, 2329, 1987, 252, 421, 4036, 4279, 7092, ... .
|
|
LINKS
|
|
|
MATHEMATICA
|
s="1"; ss={}; Do[tsn=ToString[n^2]; If[ !StringFreeQ[s, tsn], AppendTo[ss, n]; Print[n]]; s=s<>tsn, {n, 2, 99999}];
|
|
PROG
|
(Python)
def aupto(limit):
s, alst = "", []
for k in range(1, limit+1):
ss = str(k*k)
if ss in s: alst.append(k)
s += ss
return alst
|
|
CROSSREFS
|
|
|
KEYWORD
|
base,nonn
|
|
AUTHOR
|
|
|
EXTENSIONS
|
|
|
STATUS
|
approved
|
|
|
|