|
%I #20 Jun 18 2017 02:22:34
%S 1,10,73,121,121,121,121,121,121,121,121,121,121,121,121,121,121,121,
%T 121,121,121,121,121,121,121,121,121,121,121,121,121,121,121,121
%N Total number of positive integers below 10^n requiring 7 positive cubes in their representation as sum of cubes.
%C A061439(n) + A181375(n) + A181377(n) + A181379(n) + A181381(n) + A181400(n) + a(n) + A181404(n) + A130130(n) = A002283(n)
%C An unpublished result of Deshouillers-Hennecart-Landreau, combined with Lemma 3 from Bertault, Ramaré, & Zimmermann implies that a(4)-a(34) are all 121. Probably a(n) = 121 for all n > 3. - _Charles R Greathouse IV_, Jan 23 2014
%H F. Bertault, O. Ramaré, and P. Zimmermann, <a href="http://www.ams.org/journals/mcom/1999-68-227/S0025-5718-99-01071-6/">On sums of seven cubes</a>, Math. Comp. 68 (1999), pp. 1303-1310.
%H Eric W. Weisstein, <a href="http://mathworld.wolfram.com/WaringsProblem.html">MathWorld -- Waring's Problem</a>
%H <a href="/index/Rec#order_01">Index entries for linear recurrences with constant coefficients</a>, signature (1).
%F G.f.: x*(1+9*x+63*x^2+48*x^3)/(1-x). - _Colin Barker_, May 04 2012
%Y Cf. A018890
%K nonn
%O 1,2
%A _Martin Renner_, Jan 28 2011
%E a(5)-a(7) from _Lars Blomberg_, May 04 2011
%E a(8)-a(34) from _Charles R Greathouse IV_, Jan 23 2014
|
