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%I #3 Mar 31 2012 12:35:46
%S 0,1,5,64,400,1914,7589,24902,73134,188315,455127,996083,2098908,
%T 4080930,7790731,13869018,24527424,40768032,67955336,106952861,
%U 169909977,255608028,390623704,566247614,837326375,1175991196,1690928973
%N Number of distinct solutions of sum{i=1..5}(x(2i-1)*x(2i)) = 1 (mod n), with x() only in 1..n-1
%C Column 5 of A180793
%H R. H. Hardin, <a href="/A180787/b180787.txt">Table of n, a(n) for n=1..250</a>
%e Solutions for sum of products of 5 1..2 pairs = 1 (mod 3) are
%e (1*1 + 1*1 + 1*1 + 1*2 + 1*2) (1*1 + 1*1 + 1*2 + 1*2 + 2*2)
%e (1*1 + 1*2 + 1*2 + 2*2 + 2*2) (1*2 + 1*2 + 1*2 + 1*2 + 1*2)
%e (1*2 + 1*2 + 2*2 + 2*2 + 2*2)
%K nonn
%O 1,3
%A _R. H. Hardin_ Sep 20 2010
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