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A180653
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'DP(n,k)' triangle read by rows. DP(n,k) is the number of k-double-palindromes of n.
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5
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0, 0, 1, 0, 2, 1, 0, 3, 2, 1, 0, 4, 4, 4, 1, 0, 5, 3, 8, 4, 1, 0, 6, 6, 12, 12, 6, 1, 0, 7, 6, 17, 12, 19, 6, 1, 0, 8, 7, 24, 24, 20, 24, 8, 1, 0, 9, 8, 32, 21, 50, 24, 32, 8, 1, 0, 10, 10, 40, 40, 60, 60, 40, 40, 10, 1, 0, 11, 9, 49, 40, 100, 60, 98, 35, 51, 10, 1
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OFFSET
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1,5
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COMMENTS
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A k-composition of n is an ordered collection of k positive integers (parts) which sum to n. A palindrome is a word which is the same when written backwards.
A k-double-palindrome of n is a k-composition of n which is the concatenation of two palindromes, PP'=P|P', where both |P|, |P'|>=1.
For example 1123532=11|23532 is a 7-double-palindrome of 17 since both 11 and 23532 are palindromes.
Let DP(n,k) denote the number of k-double-palindromes of n.
This sequence is the 'DP(n,k)' triangle read by rows.
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REFERENCES
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John P. McSorley: Counting k-compositions of n with palindromic and related structures. Preprint, 2010.
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LINKS
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FORMULA
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EXAMPLE
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The triangle begins
0
0 1
0 2 1
0 3 2 1
0 4 4 4 1
0 5 3 8 4 1
0 6 6 12 12 6 1
0 7 6 17 12 19 6 1
0 8 7 24 24 20 24 8 1
0 9 8 32 21 50 24 32 8 1
...
For example, row 8 is: 0 7 6 17 12 19 6 1.
We have DP(8,3)=6 because there are 6 3-double-palindromes of 8: 116, 611, 224, 422, 233, and 332.
We have DP(8,4)=17 because there are 17 4-double-palindromes of 8: 1115, 5111, 1511, 1151, 1214, 4121, 1412, 2141, 1133, 3311, 1313, 3131, 1232, 2123, 3212, 2321, and 2222.
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PROG
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p(n, k) = {k*binomial((n-k%2)\2, k\2)}
q(n, k) = {if(n%2==1&&k%2==0, 0, binomial((n-1)\2, (k-1)\2))}
invphi(n) = {sumdiv(n, d, d*moebius(d))}
T(n, k) = sumdiv(gcd(n, k), d, invphi(d) * p(n/d, k/d) - moebius(d) * q(n/d, k/d)); \\ Andrew Howroyd, Sep 27 2019
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CROSSREFS
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See sequence A051159 for the triangle whose (n, k) term gives the number of k-palindromes (single-palindromes) of n.
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KEYWORD
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AUTHOR
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EXTENSIONS
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STATUS
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approved
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