OFFSET
1,149
COMMENTS
There can be one or more digits having the minimum frequency.
LINKS
Carmine Suriano, Table of n, a(n) for n = 1..1150
FORMULA
a(n) < n log phi / 10 log 10.
Heuristically, a(n) = n log phi / 10log 10 + O(sqrt(n)), where the big-O constant is roughly -0.17576.
EXAMPLE
a(98)=1 since Fib(98)=135301852344706746049 and digits 2, 8, 9 occur 1 time (minimum frequency).
CROSSREFS
KEYWORD
nonn,base
AUTHOR
Carmine Suriano, Jan 21 2011
EXTENSIONS
Formulas from Charles R Greathouse IV, Jan 21 2011
STATUS
approved