%I #7 Aug 08 2021 22:05:25
%S 5,53,928,13999,187661,2344658,28039129,325695551
%N Smallest m such that tau(m!) > 10^(10^n).
%F min{m: A027423(m) > 10^(10^n)}.
%F a(n) = A098109(10^n).
%e a(0)=5 with tau(5!) = A000005(120) = 16 > 10^(10^0) = 10.
%e a(1)=53 with tau(53!) = A000005(427...0000) = 16174080000 > 10^(10^1) = 10^10.
%K nonn,more
%O 0,1
%A _Jeff Burch_, Aug 29 2010