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A180323 Positive numbers l of the form l = A007913(k^4 - 4*k*m^3), where 1 <= k <= 5*l, 1 <= |m| <= 5*l. 1
2, 5, 6, 11, 15, 17, 29, 33, 41, 42, 43, 51, 53, 58, 62, 65, 69, 82, 85, 86, 89, 93 (list; graph; refs; listen; history; text; internal format)
OFFSET

1,1

COMMENTS

The equation x^3 + y^3 + z^3 = 0 is solvable in numbers of the form N + M*sqrt(a(n)), where M and N are integers. Moreover, it is solvable in numbers of the form N + M*sqrt(l), where l has the form l = A007913(k^4 - 4*k*m^3), where k,|m| >= 1 (without restrictions k,|m| <= 5*l). But in this more general case there could be unknown numbers l having this form; this circumstance does not allow construction of the full sequence of such l. Therefore we restrict ourselves by the condition k,|m| <= 5*l. Note that testing l with respect to this condition is rather simple by sorting all values of k,|m| <= l. One can prove that, at least, if the Fermat numbers (A000215) are squarefree, then the sequence is infinite. Conjecture (necessity of the form of l): If the equation x^3 + y^3 + z^3 = 0 is solvable in numbers of the form N + M*sqrt(l) with integer N,M, then there exist positive integers k,m such that l = A007913(k^4 - 4*k*m^3).

LINKS

Table of n, a(n) for n=1..22.

FORMULA

Let a(n) = A007913(k^4-4*k*m^3). Put g=sqrt(A008833(k^4-4*k*m^3)). Then identity A^3+B^3+C^3=0 is valid, where A=2*m^6-k^3*m^3-k^6+k*(k^3+5*m^3)*g*sqrt(a(n)); B=3*m*(k^3-m^3)*(k^2-g*sqrt(a(n))); C=k^6-8*k^3*m^3-2*m^6-k*(k^3-4*m^3)*g*sqrt(a(n)).

CROSSREFS

Cf. A007913, A008833, A000215.

Sequence in context: A015613 A135013 A239447 * A103035 A088273 A049054

Adjacent sequences:  A180320 A180321 A180322 * A180324 A180325 A180326

KEYWORD

nonn,uned,more

AUTHOR

Vladimir Shevelev, Aug 28 2010

STATUS

approved

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Last modified March 28 19:06 EDT 2017. Contains 284246 sequences.