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 A180171 Triangle read by rows: R(n,k) is the number of k-reverses of n. 4
 1, 1, 1, 1, 2, 1, 1, 3, 3, 1, 1, 4, 6, 4, 1, 1, 5, 4, 10, 5, 1, 1, 6, 9, 12, 15, 6, 1, 1, 7, 9, 19, 15, 21, 7, 1, 1, 8, 10, 24, 30, 20, 28, 8, 1, 1, 9, 12, 36, 26, 54, 28, 36, 9, 1, 1, 10, 15, 40, 50, 60, 70, 40, 45, 10, 1, 1, 11, 13, 53, 50, 108, 70, 106, 39, 55, 11, 1, 1, 12, 18, 60, 75, 120 (list; table; graph; refs; listen; history; text; internal format)
 OFFSET 1,5 COMMENTS A k-composition of n is an ordered collection of k positive integers (parts) which sum to n. Two k-compositions are cyclically equivalent if one can be obtained from the other by a cyclic permutation of its parts. The reverse of a k-composition is the k-composition obtained by writing its parts in reverse. For example the reverse of 123 is 321. A k-reverse of n is a k-composition of n which is cyclically equivalent to its reverse. For example 114 is a 3-reverse of 6 since its set of cyclic equivalents {114,411,141} contains its reverse 411. But 123 is not a 3-reverse of 6 since its set of cyclic equivalents {123,312,231} does not contain its reverse 321. REFERENCES John P. McSorley: Counting k-compositions of n with palindromic and related structures. Preprint, 2010. LINKS Robert G. Wilson v, Table of n, a(n) for n = 1..500. Petros Hadjicostas, Proofs of two formulae on the number of k-inverses of n FORMULA R(n,k) = Sum_{d|gcd(n,k)} A180279(n/d, k/d). - Andrew Howroyd, Oct 08 2017 From Petros Hadjicostas, Oct 21 2017: (Start) For proofs of these formulae, see the links. R(n,k) = Sum_{d|gcd(n,k)} phi^{(-1)}(d)*(k/d)*A119963(n/d, k/d), where phi^{(-1)}(d) = A023900(d) is the Dirichlet inverse function of Euler's totient function. G.f.: Sum_{s >= 1} phi^{(-1)}(s)*g(x^s, y^s), where phi^{(-1)}(s) = A023900(s) and g(x,y) = (x*y+x+1)*(x*y-x+1)*(x+1)*x*y/(x^2*y^2+x^2-1)^2. (End) EXAMPLE The triangle begins   1   1 1   1 2 1   1 3 3 1   1 4 6 4 1   1 5 4 10 5 1   1 6 9 12 15 6 1   1 7 9 19 15 21 7 1   1 8 10 24 30 20 28 8 1   1 9 12 36 26 54 28 36 9 1 For example row 8 is 1 7 9 19 15 21 7 1 We have R(8,3)=9 because there are 9 3-reverses of 8. In classes: {116,611,161} {224,422,242}, and {233,323,332}. We have R(8,6)=21 because all 21 6-compositions of 8 are 6-reverses of 8. MATHEMATICA f[n_Integer, k_Integer] := Block[{c = 0, j = 1, ip = IntegerPartitions[n, {k}]}, lmt = 1 + Length@ ip; While[j < lmt, c += g[ ip[[j]]]; j++ ]; c]; g[lst_List] := Block[{c = 0, len = Length@ lst, per = Permutations@ lst}, While[ Length@ per > 0, rl = Union[ RotateLeft[ per[], # ] & /@ Range@ len]; If[ MemberQ[rl, Reverse@ per[]], c += Length@ rl]; per = Complement[ per, rl]]; c]; Table[ f[n, k], {n, 13}, {k, n}] // Flatten (* Robert G. Wilson v, Aug 25 2010 *) PROG (PARI) \\ here p(n, k) is A119963, AR(n, k) is A180279. p(n, k) = binomial((n-k%2)\2, k\2); AR(n, k) = k*sumdiv(gcd(n, k), d, moebius(d) * p(n/d, k/d)); T(n, k) = sumdiv(gcd(n, k), d, AR(n/d, k/d)); for(n=1, 10, for(k=1, n, print1(T(n, k), ", ")); print) \\ Andrew Howroyd, Oct 08 2017 CROSSREFS Row sums are A180249. Cf. A023900, A119963, A180279. Sequence in context: A123264 A034930 A095142 * A140822 A212954 A299807 Adjacent sequences:  A180168 A180169 A180170 * A180172 A180173 A180174 KEYWORD nonn,tabl AUTHOR John P. McSorley, Aug 15 2010 EXTENSIONS a(56) onwards from Robert G. Wilson v, Aug 25 2010 STATUS approved

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Last modified October 21 11:15 EDT 2019. Contains 328294 sequences. (Running on oeis4.)