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A179929
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a(n) = 2^n*A(n, -1/2), A(n, x) the Eulerian polynomials.
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3
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1, 2, 2, -6, -30, 42, 882, 954, -39870, -203958, 2300562, 29677914, -120958110, -4657703958, -7059175758, 807984602874, 6667870853250, -145556787011958, -2827006784652078, 21703953751815834, 1108558810703202210
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n) = Sum_{k, 0<=k<=n} A123125(n,k)*(-1)^(n-k)*2^k
a(n) = Sum_{k, 0<=k<=n} A173018(n,k)*2^(n-k)*(-1)^k. (End)
E.g.f.: 3/(1 + 2exp(-3x)) = 1 + 2x + 2x^2/2! - 6x^3/3! - 30x^4/4! + ....
Recurrence equation: a(n+1) = 3a(n) - Sum_{k=0..n} binomial(n,k) a(k)a(n-k).
(-1)^n*a(n) are the coefficients of a delta operator associated with a sequence of polynomials of binomial type - see A195205. (End)
a(n) ~ n! * 2*3^(n+1)/(Pi^2+(log(2))^2)^(n/2+1) * (Pi*sin(n*arctan(Pi/log(2))) - log(2)*cos(n*arctan(Pi/log(2)))). - Vaclav Kotesovec, Oct 09 2013
a(n) = -3^(n+1)*Li(-n, -1/2), with Li(-n, x) = Sum_{k>=0} ((k^n)*(x^k)) the polylogarithm.
a(n) = Sum_{k=0..n} 3^(n-k)*(-1)^k*k!*S(n+1, k+1), S(m, l) the Stirling number of second kind. (End)
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MATHEMATICA
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a[n_] := Sum[3^(n-k) (-1)^k k! StirlingS2[n+1, k+1], {k, 0, n}];
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PROG
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(PARI) A179929(n) = {local(s, k, term);
term = 3^n; s = term*stirling(n+1, 1, 2);
for (k=1, n, term *= -k/3; s += term*stirling(n+1, k+1, 2); );
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CROSSREFS
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KEYWORD
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sign
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AUTHOR
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STATUS
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approved
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