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%I #13 Jan 06 2019 06:00:19
%S 1,4,6,8,12,13,15,17,23,24,31,23,29,29,34,38,36,42,38,47,44,44,50,48,
%T 49,54,60,56,60,61,60,60,70,68,77,72,71,82,68,81,78,83,82,82,89,91,
%U 102,90,98,99,103,97,90,107,107,112,111,120,109,115,118,112,111,127,128,133,117,117,117,139,136
%N Number of terms in the simple continued fraction for (e truncated to n decimal digits).
%e a(1): simple continued fraction (SCF) for 2 = 2 (1 term);
%e a(2): SCF for 2.7 = 2+1/(1+1/(2+1/3)) (4 terms);
%e a(3): SCF for 2.71 = 2+1/(1+1/(2+1/(2+1/(4+1/3)))) (6 terms).
%p Digits := 120 ;
%p A011543 := proc(n) floor(exp(1)*10^n) ; end proc:A179852 := proc(n) A011543(n-1)/10^(n-1) ; numtheory[cfrac](%) ; op(%) ; nops(%) ; end proc: # _R. J. Mathar_, Jan 14 2011
%Y Cf. A080235, A080229, A011543.
%K nonn,base,less
%O 1,2
%A _Umut Uludag_, Jan 11 2011
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