OFFSET
1,2
COMMENTS
Contains all sixth powers: suppose that y^2 = x^3 + t^6, then (y/t^3)^2 = (x/t^2)^3 + 1. The elliptic curve Y^2 = X^3 + 1 has rank 0 and the only rational points on it are (-1,0), (0,+-1), and (2,+-3), so y^2 = x^3 + t^6 has 5 solutions (-t^2,0), (0,+-t^3), and (2*t^2,+-3*t^3). - Jianing Song, Aug 24 2022
LINKS
J. Gebel, Integer points on Mordell curves [Cached copy, after the original web site tnt.math.se.tmu.ac.jp was shut down in 2017]
FORMULA
a(n) = A356711(n)^3.
CROSSREFS
KEYWORD
nonn
AUTHOR
Artur Jasinski, Jun 30 2010
EXTENSIONS
Edited and extended by Ray Chandler, Jul 11 2010
a(31)-a(35) from Max Alekseyev, Jun 01 2023
STATUS
approved