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A178511
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a(n) = (1/119)*(100^n -(-19)^n).
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4
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1, 81, 8461, 839241, 84054421, 8402966001, 840343645981, 84033470726361, 8403364056199141, 840336082932216321, 84033614424287889901, 8403361325938530091881, 840336134807167928254261, 84033613438663809363169041, 8403361344665387622099788221
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OFFSET
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1,2
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COMMENTS
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Numerators in alternating Sum_{n>=0} 19^n/100^(n+1).
Related to decimal expansion of fraction of 1/119 and Pell numbers. [In which way? - Joerg Arndt, May 14 2011]
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LINKS
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FORMULA
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a(n+1) = a(n)*100 +- 19^n with a(0)=0 and a(1)= 1.
a(n) = 81*a(n-1) + 1900*a(n-2) for n > 2.
G.f.: -x / ((19*x+1)*(100*x-1)).
(End)
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MATHEMATICA
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LinearRecurrence[{81, 1900}, {1, 81}, 20] (* Harvey P. Dale, Nov 12 2022 *)
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PROG
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(PARI) Vec(-x/((19*x+1)*(100*x-1)) + O(x^20)) \\ Colin Barker, Oct 02 2015
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CROSSREFS
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KEYWORD
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nonn,frac,easy
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AUTHOR
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STATUS
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approved
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