OFFSET
0,1
FORMULA
a(n)= 18^(2^(n-1))+1, n>0.
a(n)= 2+ product_{i<n} a(i).
a(n)= 1 + (a(n-1)-1)^2, n>1.
MATHEMATICA
Clear[a, n];
a[0] := 17;
a[n_] := a[n] = Product[a[i], {i, 0, n - 1}] + 2;
Table[a[n], {n, 0, 10}]
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Roger L. Bagula, May 27 2010
EXTENSIONS
Edited by the Assoc. Eds. of the OEIS, Jul 20 2010
STATUS
approved