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A177411
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a(n) = binomial((n+1)*2^(n+1), n)/(n+1).
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2
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1, 4, 92, 10416, 5258872, 11297164096, 100955979001152, 3709635244861142784, 556796318904269731012544, 339945532169833436692992549888, 841788571395046141591475043524725760
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OFFSET
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0,2
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LINKS
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FORMULA
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a(n) = [x^n] (1 + x)^((n+1)*2^(n+1))/(n+1).
a(n) = [x^n] Sum_{k=0..n} 2^k*(n+1)^(k-1) * log(1 + 2^k*x)^k/k!. - Paul D. Hanna, Jul 03 2010
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MATHEMATICA
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Table[Binomial[(n+1)2^(n+1), n]/(n+1), {n, 0, 20}] (* Harvey P. Dale, Feb 03 2019 *)
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PROG
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(PARI) {a(n)=binomial((n+1)*2^(n+1), n)/(n+1)}
(PARI) {a(n)=polcoeff(sum(k=0, n, 2^k*(n+1)^(k-1)*log(1+2^k*x +x*O(x^n))^k/k!), n)} \\ Paul D. Hanna, Jul 03 2010
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CROSSREFS
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KEYWORD
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nonn
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AUTHOR
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STATUS
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approved
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