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%I #6 Feb 01 2018 03:31:31
%S 1,2,22,1240,316316,343855008,1551088459936,28684932916796288,
%T 2161788213413182113760,661624062463590275090838016,
%U 820418024446932078541699530057216
%N a(n) = binomial((n+1)*2^n, n)/(n+1).
%F a(n) = [x^n] (1 + x)^((n+1)*2^n)/(n+1).
%F a(n) = [x^n] Sum_{k=0..n} (n+1)^(k-1) * log(1 + 2^k*x)^k/k!. - _Paul D. Hanna_, Jul 03 2010
%o (PARI) {a(n)=binomial((n+1)*2^n,n)/(n+1)}
%o (PARI) {a(n)=polcoeff(sum(k=0, n, (n+1)^(k-1)*log(1+2^k*x +x*O(x^n))^k/k!), n)} \\ _Paul D. Hanna_, Jul 03 2010
%Y Cf. A177411, A177400.
%K nonn
%O 0,2
%A _Paul D. Hanna_, Jun 26 2010
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