|
EXAMPLE
|
E.g.f: A(x) = 1 + x + 2*x^2/2! + 3*x^3/3! - 4*x^4/4! - 50*x^5/5! +...
log(A(x)) = 2*x/2! + 3*x^2/3! - 4*x^3/4! - 50*x^4/5! - 36*x^5/5! +...
...
Coefficients in the initial powers of A(x) begin:
[1,(1),(1), 1/2, -1/6, -5/12, -1/20, 49/120, 15/56, -457/1260,...];
[1, 2,(3),(3), 5/3, -1/6, -61/60, -17/60, 272/315, 451/630,...];
[1, 3, 6,(17/2),(17/2), 21/4, 3/5, -83/40, -187/168, 115/84,...];
[1, 4, 10, 18,(73/3),(73/3), 163/10, 131/30, -261/70, -1093/315,...];
[1, 5, 15, 65/2, 325/6,(847/12),(847/12), 1205/24, 9551/504,...];
[1, 6, 21, 53, 104, 327/2,(4139/20),(4139/20), 6469/42, 7414/105,...];
[1, 7, 28, 161/2, 1085/6, 3955/12, 4949/10,(24477/40),(24477/40),...];
[1, 8, 36, 116, 878/3, 1810/3, 15569/15, 7509/5,(114760/63),(114760/63), ...]; ...
where the coefficients in parenthesis illustrate the property
that the coefficients of x^n and x^(n+1) in A(x)^n are equal:
[x^n] A(x)^n = [x^(n+1)] A(x)^n = A138013(n)/(n-1)!,
where G(x) = e.g.f. of A138013 begins:
G(x) = 1 + x + 3*x^2/2! + 17*x^3/3! + 146*x^4/4! + 1694*x^5/5! + ...
and satisfies: exp(1 - G(x)) = 1 - x*G(x).
|