OFFSET
0,7
COMMENTS
The round function is defined here by round(x) = floor(x + 1/2).
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..910
Mircea Merca, Inequalities and Identities Involving Sums of Integer Functions J. Integer Sequences, Vol. 14 (2011), Article 11.9.1.
FORMULA
a(n) = round((2*n+1)*(2*n^2 + 2*n - 19)/432).
a(n) = floor((n+5)*(2*n^2 - 7*n + 17)/216).
a(n) = ceiling((n-4)*(2*n^2 + 11*n + 26)/216).
a(n) = round((2*n^3 + 3*n^2 - 18*n)/216).
a(n) = a(n-36) + (n+1)*(n-36) + 447, n > 35.
a(n) = 3*a(n-1) - 3*a(n-2) + a(n-3) + a(n-18) - 3*a(n-19) + 3*a(n-20) - a(n-21) with g.f. x^5*(1 - x + x^3 - x^4 + x^5 - x^6 + x^7 - x^9 + x^10) / ( (1+x) *(1 + x + x^2) *(x^2 - x + 1) *(x^6 + x^3 + 1) *(x^6 - x^3 + 1) *(x-1)^4 ). - R. J. Mathar, Dec 13 2010
EXAMPLE
a(19) = 0 + 0 + 0 + 0 + 0 + 1 + 1 + 1 + 2 + 2 + 3 + 3 + 4 + 5 + 5 + 6 + 7 + 8 + 9 + 10 = 67.
MAPLE
seq(round((2*n^3+3*n^2-18*n)/216), n=0..50)
MATHEMATICA
Accumulate[Floor[Range[0, 60]^2/36+1/2]] (* Harvey P. Dale, Sep 29 2011 *)
PROG
(Magma) [Floor((n+5)*(2*n^2-7*n+17)/216): n in [0..50]]; // Vincenzo Librandi, Apr 29 2011
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Mircea Merca, Dec 10 2010
STATUS
approved