1,3

The probability that fib(n) contains no 0's decreases to zero as n goes to infinity. Its maximum value seems to be F(184) having 39 digits, including no zeros.

Table of n, a(n) for n=1..35.

a(n) = A000045(A076564(n)). [From R. J. Mathar, Oct 18 2010]

a(7)=13 since fib(7) does not contain the digit 0.

Cf. A176253, A000045

Sequence in context: A212804 A132916 A274163 * A177247 A069041 A177372

Adjacent sequences: A177191 A177192 A177193 * A177195 A177196 A177197

nonn,base

Carmine Suriano, May 04 2010

approved