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The probability that fib(n) contains no 0's decreases to zero as n goes to infinity. Its maximum value seems to be F(184) having 39 digits, including no zeros.
Table of n, a(n) for n=1..35.
a(n) = A000045(A076564(n)). [From R. J. Mathar, Oct 18 2010]
a(7)=13 since fib(7) does not contain the digit 0.
Cf. A176253, A000045
Sequence in context: A212804 A132916 A274163 * A177247 A069041 A177372
Adjacent sequences: A177191 A177192 A177193 * A177195 A177196 A177197
Carmine Suriano, May 04 2010