OFFSET
0,1
COMMENTS
For n>2, fourth diagonal of A162611.
LINKS
B. Berselli, Table of n, a(n) for n = 0..10000
Index entries for linear recurrences with constant coefficients, signature (4,-6,4,-1).
FORMULA
From Bruno Berselli, Jun 04 2010: (Start)
G.f.: (3-11*x+13*x^2+x^3)/(1-x)^4.
a(n)-4*a(n-1)+6*a(n-2)-4*a(n-3)+a(n-4) = 0, with n>3.
a(n)+a(n-1) = 2*A081438(n-3), with n>2. (End)
G.f.: 3+x+x^2*G(0) where G(k) = 1 - x*(k+1)*(k+1)*(k+4)/(1 - 1/(1 - (k+1)*(k+1)*(k+4)/G(k+1))); (continued fraction, 3-step). - Sergei N. Gladkovskii, Oct 16 2012
MATHEMATICA
Table[n^3-3n^2+3, {n, 0, 40}] (* or *) LinearRecurrence[{4, -6, 4, -1}, {3, 1, -1, 3}, 50] (* Harvey P. Dale, May 15 2020 *)
PROG
(PARI) a(n)=n^3-3*n^2+3 \\ Charles R Greathouse IV, Jan 11 2012
CROSSREFS
KEYWORD
sign,easy
AUTHOR
Vincenzo Librandi, May 27 2010
STATUS
approved