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A176838
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Primes p such that p^3 = q//3 for a prime q, where "//" denotes concatenation.
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2
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17, 157, 257, 277, 397, 677, 877, 997, 1217, 1697, 1997, 2417, 2777, 3257, 3517, 3697, 4157, 4177, 5077, 5197, 5897, 6277, 7417, 7517, 8377, 9397, 9497, 9677, 9857, 11197, 11597, 12157, 12457, 12697, 13397, 13477, 13877, 14057, 14197, 15017, 16477, 17597, 18097
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OFFSET
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1,1
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COMMENTS
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Diophantine equation p^3 = 10 * q + 3 with side condition p and q prime. Necessarily the LSD for such primes p is e = 7 and the two least significant digit strings are "17", "57", "77" or "97".
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REFERENCES
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J.-P. Allouche and J. Shallit, Automatic Sequences, Theory, Applications, Generalizations, Cambridge University Press, 2003.
G. H. Hardy and E. M. Wright, An Introduction to the Theory of Numbers (Fifth edition), Oxford University Press, 1980.
F. Padberg, Zahlentheorie und Arithmetik, Spektrum Akademie Verlag, Heidelberg - Berlin 1999.
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LINKS
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EXAMPLE
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17^3 = 4913 = prime(94)//3, 17 = prime(7) is the first term.
157^3 = 3869893 = prime(32838)//3, 157 = prime(37) is the second term.
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MAPLE
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q:= n-> isprime(iquo(n^3, 10, 'd')) and d=3:
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MATHEMATICA
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Select[Range[7, 20000, 10], PrimeQ[#]&&PrimeQ[FromDigits[Most[IntegerDigits[ #^3]]]]&] (* Harvey P. Dale, Oct 03 2013 *)
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PROG
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(Python)
from sympy import isprime, primerange
def ok(p): q, r = divmod(p**3, 10); return r == 3 and isprime(q)
(PARI) isok(p) = if (isprime(p), my(v=divrem(p^3, 10)); isprime(v[1]) && (v[2] == 3)); \\ Michel Marcus, Sep 03 2021
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CROSSREFS
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KEYWORD
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base,nonn
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AUTHOR
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Ulrich Krug (leuchtfeuer37(AT)gmx.de), Apr 27 2010
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STATUS
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approved
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