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 A176824 a(n) = (n+1)^n mod n^n. 5
 0, 1, 10, 113, 1526, 24337, 450066, 9492289, 225159022, 5937424601, 172385029466, 5465884225969, 187964560069638, 6968912374274593, 277133723845128226, 11767703728247765249, 531431035966023003614, 25434534147318166381993, 1286040688679372821752042 (list; graph; refs; listen; history; text; internal format)
 OFFSET 1,3 LINKS FORMULA From Peter Bala, Sep 12 2012: (Start) a(n) = (n+1)^n - 2*n^n (since 2*n^n <= (n+1)^n < 3*n^n for n >= 1). In terms of the tree function T(x) = Sum_{n >= 1} n^(n-1)*x^n/n! of A000169 the e.g.f. is T(x)*(2*x + T(x)*(T(x)-2))/(x^2*(T(x)-1)^3) = x + 10*x^2/2! + 113*x^3/3! + ... . (End) a(n) = Sum_{i=1..n-1} C(n,i-1)*i^(i-1)*(n-i)^(n-i). - Vladimir Kruchinin, Sep 07 2015 a(n) = A000169(n+1) - 2*A000312(n). - Michel Marcus, Sep 07 2015, after Peter Bala MAPLE A176824:=n->(n+1)^n mod n^n: seq(A176824(n), n=1..25); # Wesley Ivan Hurt, Sep 10 2015 MATHEMATICA Table[Mod[(n+1)^n, n^n], {n, 30}] PROG (MAGMA) [(n+1)^n mod n^n: n in [1..20]]; // Vincenzo Librandi, Sep 07 2015 (PARI) first(m)=vector(m, i, ((i+1)^i) % (i^i)) \\ Anders HellstrÃ¶m, Sep 07 2015 CROSSREFS Cf. A000169, A000312, A048160. Sequence in context: A263370 A129866 A024130 * A196983 A199908 A185391 Adjacent sequences:  A176821 A176822 A176823 * A176825 A176826 A176827 KEYWORD nonn,easy AUTHOR Vladimir Joseph Stephan Orlovsky, Apr 26 2010 EXTENSIONS a(19) from Vincenzo Librandi, Sep 07 2015 STATUS approved

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Last modified September 24 17:09 EDT 2020. Contains 337321 sequences. (Running on oeis4.)