OFFSET
0,1
COMMENTS
Essentially partial sums of A061804.
Agrees with the known terms listed in A082986. Are the sequences identical?
Partial sums of A061804 (see above comment) = 1*n^4 + 2*n^3 + 2*n^2 + 1*n^1. To obtain this sequence, all elements of which are pronic numbers of pronic number index number (e.g., a(8) = 8190 is the 90th pronic number and 90 is the 9th pronic number; 9 = 8 + 1), then switch n to (n+1). - Raphie Frank, Oct 17 2012
LINKS
Vincenzo Librandi, Table of n, a(n) for n = 0..1000
Index entries for linear recurrences with constant coefficients, signature (5,-10,10,-5,1).
FORMULA
G.f.: 6*(1+x)^2/(1-x)^5.
a(n) = 6*A006325(n+2).
a(n) = 4*a(n-1) - 6*a(n-2) + 4*a(n-3) - a(n-4) + 24; a(0)=6, a(1)=42, a(2)=156, a(3)=420.
a(n) = a(-n-3). - Bruno Berselli, Sep 05 2011
MATHEMATICA
Table[n^4+6n^3+14n^2+15n+6, {n, 0, 40}] (* or *) LinearRecurrence[ {5, -10, 10, -5, 1}, {6, 42, 156, 420, 930}, 40] (* Harvey P. Dale, Mar 28 2012 *)
PROG
(Magma) [ n^4+6*n^3+14*n^2+15*n+6: n in [0..32] ];
(PARI) a(n)=n^4+6*n^3+14*n^2+15*n+6 \\ Charles R Greathouse IV, Oct 17 2012
(Python)
def A176780(n): return n*(n*(n*(n + 6) + 14) + 15) + 6 # Chai Wah Wu, Aug 30 2022
CROSSREFS
KEYWORD
nonn,easy
AUTHOR
Klaus Brockhaus, Apr 25 2010
STATUS
approved