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%I #4 Mar 31 2012 20:08:10
%S 1,0,1,1,-1,1,0,1,-1,1,1,0,0,-1,1,0,0,1,0,-1,1,1,0,0,0,0,-1,1,0,1,-1,
%T 1,0,0,-1,1,1,-1,1,0,0,0,0,-1,1,0,1,0,-1,1,0,0,0,-1,1,1,0,0,0,0,0,0,0,
%U 0,-1,1,0,0,0,1,-1,1,0,0,0,0,-1,1,1,0,0,0,0,0,0,0,0,0,0,-1,1,0,1,0,0,0,-1
%N Triangle T(n,k) read by rows. A051731(n,k)-A051731(n,k+1).
%C Matrix inverse of A134541.
%C The subsequence of A180430 beginning from the second column, divided by 2, equals this sequence. [From _Mats Granvik_, Sep 04 2010]
%e Triangle begins:
%e 1
%e 0...1
%e 1..-1...1
%e 0...1..-1...1
%e 1...0...0..-1...1
%e 0...0...1...0..-1...1
%e 1...0...0...0...0..-1...1
%e 0...1..-1...1...0...0..-1...1
%e 1..-1...1...0...0...0...0..-1...1
%e 0...1...0..-1...1...0...0...0..-1...1
%e 1...0...0...0...0...0...0...0...0..-1...1
%e 0...0...0...1..-1...1...0...0...0...0..-1...1
%Y Cf. A176702*A000012=A051731. Row sums equals A000012.
%K sign,tabl
%O 1,1
%A Mats Granvik, _Gary W. Adamson_, Apr 24 2010
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