|
|
A176388
|
|
A symmetrical triangle:t(n,m)=Floor[(n!/Floor[n/2]!^2)*(Exp[ -(m - n/2)^2/( 2*((n + 1)/4)^2)] - Exp[ -(n/2)^2/(2*((n + 1)/4)^2)]) + 1]
|
|
0
|
|
|
1, 1, 1, 1, 2, 1, 1, 4, 4, 1, 1, 3, 5, 3, 1, 1, 11, 21, 21, 11, 1, 1, 6, 13, 16, 13, 6, 1, 1, 34, 76, 106, 106, 76, 34, 1, 1, 15, 33, 50, 56, 50, 33, 15, 1, 1, 112, 258, 402, 493, 493, 402, 258, 112, 1, 1, 40, 91, 146, 188, 204, 188, 146, 91, 40, 1
(list;
table;
graph;
refs;
listen;
history;
text;
internal format)
|
|
|
OFFSET
|
0,5
|
|
COMMENTS
|
The sequence is an approximate adjusted normal probability distribution made integer by the Floor[] operation.
Row sums are:
{1, 2, 4, 10, 13, 66, 56, 434, 254, 2532, 1136,...}.
|
|
LINKS
|
|
|
FORMULA
|
t(n,m)=Floor[(n!/Floor[n/2]!^2)*(Exp[ -(m - n/2)^2/( 2*((n + 1)/4)^2)] - Exp[ -(n/2)^2/(2*((n + 1)/4)^2)]) + 1]
|
|
EXAMPLE
|
{1},
{1, 1},
{1, 2, 1},
{1, 4, 4, 1},
{1, 3, 5, 3, 1},
{1, 11, 21, 21, 11, 1},
{1, 6, 13, 16, 13, 6, 1},
{1, 34, 76, 106, 106, 76, 34, 1},
{1, 15, 33, 50, 56, 50, 33, 15, 1},
{1, 112, 258, 402, 493, 493, 402, 258, 112, 1},
{1, 40, 91, 146, 188, 204, 188, 146, 91, 40, 1}
|
|
MATHEMATICA
|
t0[n_, m_] = Floor[(n!/Floor[n/2]!^2)*(Exp[ -(m - n/2)^2/(2*((n + 1)/4)^2)] - Exp[ -(n/2)^2/(2*((n + 1)/4)^2)]) + 1];
Table[Table[t0[n, m], {m, 0, n}], {n, 0, 10}];
Flatten[%]
|
|
CROSSREFS
|
|
|
KEYWORD
|
|
|
AUTHOR
|
|
|
STATUS
|
approved
|
|
|
|