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a(n) = sigma(d(n)) where d(n) is n-th divisor of 101010 (n=1..64).
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%I #8 Nov 27 2015 17:07:28

%S 1,3,4,6,12,8,18,14,24,24,32,42,72,48,38,56,96,84,144,114,168,112,192,

%T 152,252,336,228,336,576,456,304,448,684,1008,672,532,912,1344,912,

%U 1216,2016,1596,2736,1824,2688,2128,3648,3192,5472,8064,6384,4256,7296,9576

%N a(n) = sigma(d(n)) where d(n) is n-th divisor of 101010 (n=1..64).

%C 101010 is the 71st birthday of NJAS!

%t DivisorSigma[1,#]&/@Divisors[101010] (* _Harvey P. Dale_, Nov 27 2015 *)

%o (PARI) dv=divisors(101010);for(n=1,#dv,print1(sigma(dv[n]),", "))

%K easy,fini,full,nonn

%O 1,2

%A _Zak Seidov_, Oct 10 2010