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A175892
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Row a(0) = A000027; row a(n) for n > 0 is the sequence of natural numbers up to each k in row a(n-1).
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1
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1, 1, 2, 1, 1, 3, 1, 1, 2, 4, 1, 1, 1, 1, 5, 1, 1, 1, 2, 2, 6, 1, 1, 1, 1, 1, 3, 7, 1, 1, 1, 1, 2, 1, 1, 8, 1, 1, 1, 1, 1, 1, 2, 2, 9, 1, 1, 1, 1, 1, 2, 1, 1, 3, 10, 1, 1, 1, 1, 1, 1, 1, 1, 2, 4, 11, 1, 1, 1, 1, 1, 1, 2, 1, 2, 3, 1, 12, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 1, 2, 13, 1, 1, 1, 1, 1, 1, 1, 2, 1, 1, 1, 1
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OFFSET
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0,3
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COMMENTS
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Table is read by diagonals. Row a(1) is A002260.
Is there any column past C(2) such that every element but the first is 1?
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LINKS
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EXAMPLE
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Row 0: 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 ... (A000027)
Row 1: 1, 1, 2, 1, 2, 3, 1, 2, 3, 4 ... (A002260)
Row 2: 1, 1, 1, 2, 1, 1, 2, 1, 2, 3 ...
Row 3: 1, 1, 1, 1, 2, 1, 1, 1, 2, 1 ...
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PROG
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(Python)
out = [list(range(1, 143))]
for row in range(1, 142):
out.append([])
for column in range(142):
out[row].extend(range(1, out[row - 1][column] + 1))
if len(out[row]) > 143: break
n = 0
for diagonal in range(142):
x = diagonal
while x >= 0:
print(n, out[x][diagonal - x])
n += 1
x -= 1
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CROSSREFS
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KEYWORD
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AUTHOR
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STATUS
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approved
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