OFFSET
1,2
COMMENTS
a(1)=1, then a(2n) = (the least cube > a(2n-1)) - a(2n-1), and a(2n+1) = (the least square > a(2n)) - a(2n).
Period of length 10: {7,2,6,3,5,4,4,5,3,1}.
LINKS
Index entries for linear recurrences with constant coefficients, signature (0,0,0,0,0,0,0,0,0,1).
FORMULA
a(1)=1, afterwards a(n)=A130532(n+7).
MATHEMATICA
LinearRecurrence[{0, 0, 0, 0, 0, 0, 0, 0, 0, 1}, {1, 7, 2, 6, 3, 5, 4, 4, 5, 3}, 120] (* or *) PadRight[ {}, 120, {1, 7, 2, 6, 3, 5, 4, 4, 5, 3}] (* Harvey P. Dale, Jul 05 2022 *)
CROSSREFS
KEYWORD
nonn
AUTHOR
Zak Seidov, May 03 2010
STATUS
approved