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A174887
Numbers m such that sum of cubes of their digits > m.
1
2, 3, 4, 5, 6, 7, 8, 9, 13, 14, 15, 16, 17, 18, 19, 23, 24, 25, 26, 27, 28, 29, 32, 33, 34, 35, 36, 37, 38, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56, 57, 58, 59, 60, 61, 62, 63, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81
OFFSET
1,1
COMMENTS
The sequence is finite and contains 565 numbers. If m > 1999, sum of cubes of digits < m.
LINKS
EXAMPLE
53 is in the sequence because 5^3 + 3^3 = 152 > 53.
MAPLE
A055012 := proc(n) add(d^3, d=convert(n, base, 10)) ; end proc:
isA174887 := proc(n) A055012(n)>n ; end proc:
for n from 1 to 100 do if isA174887(n) then printf("%d, ", n) ; end if; end do:
CROSSREFS
Cf. A055012.
Sequence in context: A342264 A094823 A032973 * A092598 A247811 A007377
KEYWORD
nonn,base,fini,full
AUTHOR
Michel Lagneau, Dec 02 2010
STATUS
approved