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%I #15 Aug 22 2017 15:05:22
%S 0,1,1,1,1,2,1,1,2,3,3,3,3,2,3,4,5,5,5,4,3,5,6,7,5,8,8,6,8,10,10,8,6,
%T 7,8,8,10,7,9,9,10,11,10,9,10,9,11,11,11,11,12,13,13,12,14,10,14,17,
%U 15,13,13,12,15,14,16,15,12,14,15,15,16,15,15,15,16,13,12,16,17,14,20,20,20
%N Floor(10^n/4) - A173228(n).
%C a(n) = A055223(n) if n>1.
%H Antonio M. Oller-Marcen, José María Grau, <a href="http://arxiv.org/abs/1002.4175">On the base b expansion of the number of trailing zeros of b^k!</a>, arXiv:1002.4175 [math.NT], 2010, and <a href="https://cs.uwaterloo.ca/journals/JIS/VOL14/Oller/oller3.html">J. Int. Seq. 14 (2011) 11.6.8</a>
%K easy,nonn
%O 1,6
%A _José María Grau Ribas_, Mar 29 2010