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A174401 Sequence showing kinds of "waves", built as follows in comments. 0
1, 6, 26, 2, 100, 2, 4, 2, 396, 2, 4, 2, 12, 2, 4, 2, 1580, 2, 4, 2, 12, 2, 4, 2, 44, 2, 4, 2, 12, 2, 4, 2, 6316, 2, 4, 2, 12, 2, 4, 2, 44, 2, 4, 2, 12, 2, 4, 2, 172, 2, 4, 2, 12, 4, 2, 44, 2, 4, 2, 12, 2, 4, 2, 25260, 2, 4, 2, 12, 2, 4, 2, 44, 2, 4, 2, 12, 2, 4, 2, 172, 2, 4, 2, 12, 2, 4, 2, 44 (list; graph; refs; listen; history; text; internal format)
OFFSET

0,2

COMMENTS

With the particular values: a(2^k)=(74*4^(k-1))+4)/3 and also for example: a(3*2^(k-1))=(8*4^(k-2)+4)/3, a(7*2^(k-2))=a(5*2^(k-2))=(8*4^(k-3)+4)/3, the recurrence rule is: if we denote U the finited sequence of numbers between a(2^k) and a(2^(k+1)), the finited sequence of numbers between a(2^(k+1)) and a(2^(k+2)) is given by: U - ((8*4^(k-1)+4)/3) - U. It seems that this sequence gives the numbers of "1" in the sets of "1" in the sequence A174353.

LINKS

Table of n, a(n) for n=0..87.

EXAMPLE

a(8)=a(2^3)=(74*4^2+4)/3=396. Between a(8)=396 and a(16)=1580, the numbers are: 2, 4, 2, 12, 2, 4, 2. Then between a(16) and a(32)= 6316, the numbers of the sequence a are: 2, 4, 2, 12, 2, 4, 2 , 44=(8*4^2+4)/3, 2, 4, 2, 12, 2, 4, 2. So have we obtained in the next step: 1580, 2, 4, 2, 12, 2, 4, 2 , 44, 2, 4, 2, 12, 2, 4, 2, 6316.

CROSSREFS

Cf. A174353, A174354.

Sequence in context: A041064 A005938 A157025 * A036175 A239178 A154869

Adjacent sequences:  A174398 A174399 A174400 * A174402 A174403 A174404

KEYWORD

easy,nonn

AUTHOR

Richard Choulet, Mar 18 2010

STATUS

approved

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Last modified July 20 16:15 EDT 2019. Contains 325185 sequences. (Running on oeis4.)